# SSC CGL Quantitative Aptitude – Time, Speed and Distance Problems

SSC CGL Quantitative Aptitude is arguably one of the toughest section of SSC CGL Exam. All the topics in this section require extra effort and practice. Mastering the topics in SSC CGL Quantitative Aptitude section is the key to achieving an above average score in the SSC CGL 2018 Exam. Therefore, in our today’s blog, we will cover an important topic – Time Speed and Distance for you all.

This blog contains formulae for the topic, 2 video lessons and some sample questions for practice along with detailed solutions

### SSC CGL Quantitative Aptitude: Formulae

• Distance = Speed * Time
• Speed = Distance/Time
• Time = Distance/Speed

Time, Speed and Distance problems also require converting the values from Km/hr to m/sec and vice a versa. The short cut formula for doing this is –

• To convert form Km/Hr to M/Sec = Multiple the value by 5/18
• To convert M/sec value to Km/Hr = Multiple the value by 18/5

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### SSC CGL Quantitative Aptitude: Types of problems

• Trains – Trains crossing each other, overtaking one another, passing the platform, passing an individual, passing a pole, etc
• Cars/Vehicles – 2 cars starting from the same point, 2 cars starting from opposite ends, multiple vehicles with different speeds etc
• Running/Walking – covering distance on foot at different speeds

### SSC CGL Quantitative Aptitude – Videos

Time Speed and Distance – Useful Tricks

Time, Speed and Distance – Advanced Level Problems

### SSC CGL Quantitative Aptitude: Sample Questions

Q1. A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?

(a) 50 meters

(b) 100 meters

(c) 120 meters

(d) None of above

Explanation:

Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr

Distance covered in 6 minutes = 1/60∗6=1/10=100meters

So the distance between them after 6 minutes = 200 – 100

= 100 meters

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Q2. A man in a train notices that he can count 41 telephone posts in one minute. If they are known to be 50 metres apart, then at what speed is the train travelling?

(a) 100 Km/hr

(b) 110 Km/Hr

(c) 120 Km/Hr

(d) 150 Km/Hr

Explanation:

Number of gaps between 41 poles = 40

So the total distance between 41 poles = 40*50

= 2000 meter = 2 km

In 1 minute train is moving 2 km/minute.

Speed in hour = 2*60 = 120 km/hour

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Q3. A cyclist covers a distance of 750 meters in 2 minutes 30 seconds. What is the speed in km/hr of the cyclist?

(a) 18 Km/hr

(b) 20 Km/Hr

(c) 15 Km/Hr

(d) 7.5 Km/Hr

Explanation:

Speed=Distance/Time

Distance=750meter

Time=2 min 30 sec = 150 sec

Speed = 750/150 = 5m/sec

= 5∗18/5km/hr = 18km/hr

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Q4. Excluding stoppages, the speed of a bus is 54 km/h and including stoppages, it is 45 km/h. For how many minutes does the bus stop per hour?

(a) 5 mins

(b) 10 mins

(c) 15 mins

(d) 7.5 12 mins

Explanation:

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km = (9/54) hour

= (1/6) * 60 minutes

= 10 minutes

We hope you this blog and find the information given here useful for preparation of SSC CGL Quantitative Aptitude Section.

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