Solve these **Data Interpretation Questions** in the minimum time possible with accuracy. DI Questions are an indispensable part of the both the **Prelims & Mains Phase** of various **Bank and Government Exams**. We have come up with some of the missing Tabular DI Questions here in this blog. Give them a try and solve in the minimum time possible for the upcoming **SBI Clerk**, **RBI Assistant**, **SBI PO** and **IBPS exams**.

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**Practice Data Interpretation Questions – Missing Tabular DI **

**For Bank & Govt. Exams**

**Q. I. The table shows the total no. of emails received in inbox by different users and the percentage of emails read by the users and the total no. of emails received in a month.**

Note:

- Total no. of mails received = total mails received in inbox + total no. of spam emails received.
- Spam mails are not read by users.

Users |
Total No. of MailsReceived in Inbox |
% of Inbox MailsRead by the Users |
Total No. ofSpam-Mails Received |
---|---|---|---|

X |
725 | 68% | 88 |

Y |
840 | 65% | 82 |

Z |
800 | _ | 152 |

K |
_ | 45% | 92 |

L |
580 | _ | 76 |

**Q. Inbox mails read by user Z is what percentage of total mails received in inbox of Z given that inbox mails read by user Z is 125% of total spam mails received by user K?**

a. 14.375%

b. 19.25%

c. 24.125%

d. None

e. 11.215%

**Answer: a**

**Q. Average no. of emails received in inbox by user X, Y & K is 750% of average no. of spam mail received by user X, Y & K. Then find the total no. of mails received by user K?**

a. 492

b. 528

c. 426

d. 482

e. None of these

**Answer: a**

**Q. Total no. of mails received by K is approximately what percentage of inbox emails read by user X given that mails received in the inbox by K is thrice of mails received in spam by K?**

a. 54%

b. 62%

c. 78%

d. 68%

e. 72%

**Answer: e**

**Q. No. of inbox emails which are not read by user Z is 150% more than emails received in spam by user X. Then, find the average of inbox emails read by the user Z & Y?**

a. 678

b. 618

c. 425

d. 563

e. 589

**Answer: d**

**Q.II. Upstream Distance = Downstream Distance, if not stated**

**Total time taken = Time (Downstream) + Time (Upstream)**

Days |
Upstream Distance in KM |
Speed of the Boat (Km/hr) |
Speed of the Stream (Km/hr) |
Total Time in hour |
---|---|---|---|---|

Mon |
320 | _ | 4 | _ |

Tues |
_ | _ | _ | 75 |

Wed |
270 | _ | 6 | _ |

Thurs |
_ | 11 | 7 | _ |

Fri |
324 | _ | _ | 72 |

**Q. On Friday, if the ratio of the speed of the boat to the speed of the stream is 2:1, what is the difference between the time taken by the boat to go upstream and the time taken by the boat to go downstream?**

a. 36 hours

b. 54 hours

c. 45 hours

d. 72 hours

e. 65 hours

Answer: a

**Q. On Thursday, the difference between the time taken by the boat to cover X km upstream and (X+120) Km downstream is 26 hours. Had the boat covered same distance upstream as downstream, what would be the difference in time taken then?**

a. 58 hours

b. 62 hours

c. 48 hours

d. 56 hours

e. 64 hours

Answer: d

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