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Previous Year Questions

Get Detailed Solutions for Previous Year Questions for Bank, SSC, Railways and Other Popular Government Exams

Question :

A six-digit number 11p9q4 is divisible by 24. Then the greatest possible value for pq is:

1. 42

2. 32

3. 56

4. 68

Correct Answer : 3
Solution :

A number is divisible by 24 means a number is divisible by both 3 and 8 individually.

11p9q4 is divisible by 8 means last three digits (9q4) must be divisible by 8.

Possible values of q = 0, 4, 8 [We cannot take 0 as a value of 'q' because it will make the product 0 and we will never get the maximum possible value.]

When q = 4:

Sum of digits of number = 1 + 1 + p + 9 + 4 + 4 = 19 + p

Possible values of p = 2, 5, 8

Possible values of 'pq' = 8, 20, 32

When q = 8:

Sum of digits of number = 1 + 1 + p + 9 + 8 + 4 = 23 + p

Possible values of p = 1, 4, 7

Possible values of 'pq' = 8, 32, 56

So, maximum possible value of 'pq' = 56

SSC CGL Tier II Previous Year Papers

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SSC CGL Tier II - Past Year Papers Test Series

SSC CGL Tier II - Jan 20, 2025

390 150 2 Hrs 15 Min

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SSC CGL Tier II - Oct 26, 2023

390 150 2 Hrs 15 Min

SSC CGL Tier II - Mar 7, 2023

390 150 2 Hrs 15 Min

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390 150 2 Hrs 15 Min

SSC CGL Tier II - Mar 3, 2023

390 150 2 Hrs 15 Min

SSC CGL 2024 Tier II Test Series

SSC CGL 2024 Tier II - 1

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