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Question :

Bag A contains some red balls and Bag B contains some blue balls. They are mixed up together and two balls are picked up randomly. The probability of being one ball red and one ball blue is 16/33. If the number of blue balls is 50% of the number of red balls, then find the difference between the number of red balls and the number of blue balls?

1. 4

2. 6

3. 8

4. 12

5. None of these

Correct Answer : 1
Solution :

Let the number of red balls = 2X

So, the number of blue balls = X

According to the question-

=> (2XC1 * XC1)/(3XC2) = 16/33

=> (2X * x)/3X(3X - 1)/2 = 16/33

=> 4X2/(9X2 - 3X) = 16/33

=> X2/(3X2 - 1) = 4/11

=> 11X2 = 12X2 - 4X

=> X = 4

The number of red balls = 8

The number of blue balls = 4

Required difference = 8 - 4 = 4

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