Five persons A, B, C, D and E have different weights. No two persons have the same weight.
A is not lighter than E. Two persons are lighter than E.
| | Case 1 | Case 2 |
| Sr. no | Persons | Persons |
| 1 | A | |
| 2 | | A |
| 3 | E | E |
| 4 | | |
| 5 | | |
C is heavier than D but lighter than B.
Neither B nor E is the heaviest person. Thus, case 2 is invalid.
| | Case 1 |
| Sr. no | Persons |
| 1 | A |
| 2 | B |
| 3 | E |
| 4 | C |
| 5 | D |
The weight of E is 17kg.
Therefore, the final sequence is:
| Sr. no | Persons |
| 1 | A |
| 2 | B |
| 3 | E = 17kg |
| 4 | C |
| 5 | D |
Weight of E is 17kg and weight of D is 14kg.
So, the weight of C is more than 14kg and less than 17kg.
So, option (a) is correct.
Study Notes
Category
