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Previous Year Questions

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Question :

Directions : In a birthday party, chocolates are distributed among six children. Each one has different number of chocolates. Bob has less chocolates than Ela. Dia has more chocolates than only two children. Ansh has less chocolates than Chiu but more chocolates than Fin. The one who has second highest number of chocolates has 35 chocolates. Ansh has 28 chocolates. Chiu does not have the highest number of chocolates. Chiu does not have odd number of chocolates.

Who among the following has highest number of chocolates?

1. Chiu

2. Ela

3. Ansh

4. Fin

5. Bob

Correct Answer : 2
Solution :

Dia has more chocolates than only two children.

Highest Lowest
Dia

Ansh has less chocolates than Chiu but more chocolates than Fin.

Chiu does not have more number of chocolates.

Highest Lowest
Case 1ChiuDiaAnshFin
Case 2ChiuDiaAnshFin
Case 3ChiuFinDiaAnsh

Bob has less chocolates than Ela.

The one who has second highest number of chocolates has 35 chocolates.

Chiu does not have odd number of chocolates.

Thus, Case 1 and Case 3 get cancelled.

Highest Lowest
Case 1ElaBobChiuDiaAnshFin
35

Ansh has 28 chocolates.

Highest Lowest
ElaBobChiuDiaAnshFin
3528

This is the final arrangement.

Ela has highest number of chocolates.

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