Company A:
Let total employees in department Z = 3x
Total employees in department X = 133(1/3)% of 3x = 4x
Total employees in department Y = 4x * (11/13) = 44x/13
According to the question:
(44x/13) - 3x = 5
44x - 39x = 65
x = 13
Total employees in department Z = 3x = 39
Total employees in department X = 4x = 52
Total employees in department Y = 44x/13 = 44
Company B:
Total employees in department Y = 138(6/13)% of 39 = 54
Total employees in department X = 54 * (2/3) = 36
Total employees in department Z = 250% of (54 - 36) = 45
Company C:
Let total employees in department X and Z is 8x and 10x respectively.
(8x + 10x)/2 = 36
x = 4
Total employees in department X = 8x = 32
Total employees in department Z = 10x = 40
Total employees in department Y = 5% of (32 * 40) = 64
| Company | Total employees in X | Total employees in Y | Total employees in Z |
| A | 52 | 44 | 39 |
| B | 36 | 54 | 45 |
| C | 32 | 64 | 40 |
Average number of employees in all the three departments of company A = (52 + 44 + 39)/3 = 45
Average number of employees in all the three departments of company B = (36 + 54 + 45)/3 = 45
Required difference = 45 - 45 = 0
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