Let B's administered be '2X' questions
B's attempted = 2X * 50/100 = X questions
A + C (Attempted) = 145
C's attempted = B's attempted
A's attempted = 145 - X
A's administered = 2X - 20
C's administered = 130
Let the total question attempted by A, B, and C be 'Y'
145 - X + X + X = Y
Y = 145 + X .. (i)
Total questions administered by A, B, and C = 2Y
2X - 20 + 130 + 2X = 2Y
110 + 4X = 2Y
Y = 55 + 2X ... (ii)
From (i) and (ii)
X = 90
Y = 235
| Administered | Attempted |
| A | 160 | 55 |
| B | 180 | 90 |
| C | 130 | 90 |
Attempted by A = 55
Administered by B = 180
Hence, the required ratio = 55/180 = 11/36
Study Notes
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