The total raw material left and finished products in Kolkata = The total raw material left and finished products in Surat
15Y + 6X + 4Y + 8X - 2Y = 5X + 3.5Y + 8.5X + 1.25Y + 9X - 0.5Y
17Y + 14X = 22.5X + 4.25Y
8.5X = 12.75Y
X = 3Y/2 ... (i)
The total raw material left and finished products in Delhi = 4000
4X + 7Y + 8X + 10X = 4000
22X + 7Y = 4000
From (i)
22 * 3Y/2 + 7Y = 4000
33Y + 7Y = 4000
40Y = 4000
Y = 100
X = 150
The total raw material left and finished products in Mumbai in Factory A and Factory B = 1000 * 2 = 2000
The total raw material left and finished products in Mumbai in Factory B and Factory C = 900 * 2 = 1800
The total raw material left and finished products in Mumbai in Factory C and Factory A = 700 * 2 = 1400
The total raw material left and finished products in Mumbai in Factory A, Factory B, and Factory C = (2000 + 1800 + 1400)/2 = 2600
The total raw material left and finished products in Mumbai in Factory A = 2600 - 1800 = 800
The total raw material left and finished products in Mumbai in Factory B = 2600 - 1400 = 1200
The total raw material left and finished products in Mumbai in Factory C = 2600 - 2000 = 600
| The average of raw material left and finished products in Factory A and Factory B | The average of raw material left and finished products in Factory B and Factory C | The average of raw material left and finished products in Factory C and Factory A | The raw material left and finished products in Factory A | The material left and finished products in Factory B | The raw material left and finished products in Factory C |
Mumbai | 1000 | 900 | 700 | 800 | 1200 | 600 |
Delhi | 1300 | 1200 | 1500 | 1600 | 1000 | 1400 |
Kolkata | 1500 | 1300 | 1000 | 1200 | 1800 | 800 |
Pune | 1700 | 1300 | 1600 | 2000 | 1400 | 1200 |
Surat | 1100 | 1400 | 1300 | 1000 | 1200 | 1600 |
The total raw materials left and finished products in Factory B in Kolkata = 1800
The total raw materials left and finished products in Factory B in Pune = 1400
The total raw materials left and finished products in Factory B in Surat = 1200
Hence, the required value = 1800 + 1400 + 1200 = 4400