Six persons - A, B, C, D, E and F have different numbers of chocolates.
Atleast three people have less chocolates than B.
| Case 1 | | Case 2 | | Case 3 | |
| Sr. no | People | No. of chocolates in descending order | People | No. of chocolates in descending order | People | No. of chocolates in descending order |
| 1 | | | | | B | |
| 2 | | | B | | | |
| 3 | B | | | | | |
| 4 | | | | | | |
| 5 | | | | | | |
| 6 | | | | | | |
Only three persons have different numbers of chocolates between B and E, who have more chocolates than F. Thus, case 1 and case 2 are invalid.
F has 200 chocolates.
| Case 3 | |
| Sr. no | People | No. of chocolates in descending order |
| 1 | B | |
| 2 | | |
| 3 | | |
| 4 | | |
| 5 | E | |
| 6 | F | 200 |
A has more chocolates than C and less than D. D has 700 chocolates.
| Sr. no | People | No. of chocolates in descending order |
| 1 | B | |
| 2 | D | 700 |
| 3 | A | |
| 4 | C | |
| 5 | E | |
| 6 | F | 200 |
One of the persons has 900 chocolates.
Therefore, the final arrangement is:
| Sr. no | People | No. of chocolates in descending order |
| 1 | B | 900 |
| 2 | D | 700 |
| 3 | A | |
| 4 | C | |
| 5 | E | |
| 6 | F | 200 |
C can have chocolates between 200 to 700. So, we cannot determine the numbers of chocolates with C.
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