Six persons - P, Q, R, S, T and U have different heights.
Atleast three persons are shorter than Q.
| | Case 1 | Case 2 | Case 3 |
| Sr. no | Heights (descending order) | Heights (descending order) | Heights (descending order) |
| 1 | | | Q |
| 2 | | Q | |
| 3 | Q | | |
| 4 | | | |
| 5 | | | |
| 6 | | | |
The number of persons shorter than U is equal to the number of persons taller than T.
Q and S are shorter than T. Thus, case 3 is invalid.
| | Case 1 | Case 1a | Case 2 |
| Sr. no | Heights (descending order) | Heights (descending order) | Heights (descending order) |
| 1 | T | | T |
| 2 | | T | Q |
| 3 | Q | Q | |
| 4 | | | |
| 5 | | U | |
| 6 | U | | U |
Two persons have different heights between P and S. Thus, case 2 is invalid.
| | Case 1 | Case 1a |
| Sr. no | Heights (descending order) | Heights (descending order) |
| 1 | T | P |
| 2 | P/S | T |
| 3 | Q | Q |
| 4 | | S |
| 5 | P/S | U |
| 6 | U | |
Neither P nor R is the shortest person. Thus, case 1a is invalid.
R is shorter than P.
Therefore, the final arrangement is:
| Sr. no | Heights (descending order) |
| 1 | T |
| 2 | P |
| 3 | Q |
| 4 | R |
| 5 | S |
| 6 | U |
R is the third shortest person.
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