Previous Year Questions

The given series is:

5 8 E ∞ R $ 1 T U & 3 L @ 4 O 3 % B 6 Ψ I H 6 A 2 ÷ D Σ 7 C X 9 « G

Step 1: Each element which is immediately followed by an alphabet and immediately preceded by an odd digit should be arranged immediate to the right of 'Ψ' as in the same order in the given series.

Thus, such elements are:

5 8 E ∞ R $ 1 T U & 3 L @ 4 O 3 % B 6 Ψ I H 6 A 2 ÷ D Σ 7 C X 9 « G

So,

5 E ∞ R $ 1 U & 3 L @ 4 O 3 B 6 Ψ 8 T % C « I H 6 A 2 ÷ D Σ 7 X 9 G

Step 2: Each such alphabet which is immediately not followed by another alphabet and immediately not preceded by the digit should be arranged between Σ and 7 in the reverse alphabetical order in the series thus formed after step 1.

So, such alphabets are:

Step 2:

5 E ∞ R $ 1 U & 3 L @ 4 O 3 B 6 Ψ 8 T % C « I H 6 A 2 ÷ D Σ 7 X 9 G

So, finally we get:

5 E ∞ $ 1 U & 3 L @ 4 O 3 B 6 Ψ 8 T % « I 6 A 2 ÷ Σ R H D C 7 X 9 G

If each alphabet which is immediately succeeded by either a symbol or digit is dropped, then we get:

5 ∞ $ 1 & 3 @ 4 3 6 Ψ 8 % « 6 2 ÷ Σ R H D 7 9 G

So, the symbol % appears 13^th from the left end.