(i) Given, PQ=QR,
Therefore, ΔPOR is an isosceles triangle.
Hence, statement (i) is correct.
(ii) The centroid of a triangle is the point of intersection of all the three medians of a triangle.
When we draw, line PO to point S on side QR and S is not mid-point.
So, QS ≠ SR.
Hence, O is not the centroid of ΔPQR.
Hence, statement (ii) is not correct.
(iii) ΔPQO is congruent to ΔRQO.

Given PQ = QR
And ∠OPR=∠ORP So, PO = OR
In ∆PQO and ∆RQO,
PQ = RQ
And PO = RO
QO = QO (common side)
Hence, ΔPQO is congruent to ΔRQO.
Hence, statement (iii) is correct.