Previous Year Questions

Root of equation I = 3/2

I: (B - 1)*(3/2)² - (2A - 1)*(3/2) + 5B = 0

9B - 9 - 12A + 6 + 20B = 0

29B - 12A = 3

A = (29B - 3)/12

Since, B is a positive multiple of 3 and less than 10.

B = 3 or 6 or 9

When B = 3

A = (29*3 - 3)/12 = 7

When B = 6

A = (29*6 - 3)/12 = 14.25 (not an integer)

When B = 9

A = (29*9 - 3)/12 = 21.5 (not an integer)

A = 7 and b = 3

I: (B - 1)x² - (2A - 1)x + 5B = 0

2x² - 13x + 15 = 0

(2x - 3)(x - 5) = 0

x = 3/2, 5

II: 2By² - (AB + 5)y + AB = 3

6y² - 26y + 24 = 0

3y² - 13y + 12 = 0

(3y - 4)(y - 3) = 0

y = 4/3, 3

Different between the roots of equation I = 5 - 3/2 = 7/2

Different between of roots of equation II = 3 - 4/3 = 5/3

Required percentage = [(7/2 - 5/3)/5/3]*100 % = (11/6)*60 % = 110%