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Question :

In two matches 1st and 2nd, the ratio of the number of runs scored by a batsman was 11: 15 respectively. In 3rd match, he scored 50% more than that of the 1st match then the average runs of three matches became 170. What was the average runs scored by him in 1st and 3rd match?

1. 110

2. 135

3. 112.5

4. 170

5. 165

Correct Answer : 5
Solution :

Let in 1st match, runs scored by the batsman be 11a then in second match, the runs scored by the batsman = 15a

In 3rd match, runs scored by the batsman = 150% of 11a = 16.5a

The sum = 11a + 15a + 16.5a = 42.5a = 170*3

a = 12

The runs scored by the batsman in 1st and 3rd match together = 11a + 16.5a = 27.5a = 27.5*12 = 330

The required average = 330/2 = 165

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