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Previous Year Questions

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Question :

Set A contains 7 consecutive odd multiples of 7 and set B contains 5 consecutive odd multiples of 5 such that first term of A is equal to the last term of B and average of all the terms of set B is 85. Then find the average of first three terms of set A.

1. 126

2. 133

3. 112

4. 105

5. 119

Correct Answer : 5
Solution :

A = {x, x + 14, x + 28, x + 42, x + 56, x + 70, x + 84}

B = {y, y + 10, y + 20, y + 30, y + 40}

According to the question:

x = y + 40 ........ (1)

[y + (y + 10) + (y + 20) + (y + 30) + (y + 40)]/5 = 85

5y = 425 - 10 - 20 - 30 - 40

y = 65

x = y + 40

x = 105

A = {105, 119, 133, 147, ...}

Required average = (105 + 119 + 133)/3

= 119

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