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Question :

The average of five consecutive positive even numbers is (M3 + 1) and the average of five consecutive positive odd numbers is (2X - 5). C2 - 6C + M = 0, where M is a prime number. If X2 + 3MX - 184 = 0, then find the difference between the largest positive odd number and the smallest positive even number.

1. 131

2. 137

3. 135

4. 139

5. 133

Correct Answer : 5
Solution :

Let the largest positive odd number and smallest positive even number be 'a' and 'b' respectively.

C2 - 6C + M = 0

The sum of roots of equation = β + α = 6

The products of roots of the equation = β. α

If the product of the roots of the equation is a prime number, then the sum of the equation is 1 more than the products of the equation.

So, M = 5

X2 + 3MX - 184 = 0

X2 + 3 * 5X - 184 = 0

X2 + 15X - 184 = 0

X2 + 23X - 8X - 184 = 0

X (X + 23) - 8 (X + 23) = 0

(X - 8) (X + 23) = 0

X = 8, -23

If X = 8

The average of five consecutive positive odd numbers = 2X - 5

= 28 - 5

= 251

If X = - 23

The average of five consecutive positive odd numbers = 2X - 5

= 2-23 - 5

= 1/223 - 5 [not satisfied]

A/Q

b + b + 2 + b + 4 + b + 6 + b + 8 = 5 (M3 + 1)

5b + 20 = 5 (53 + 1)

b + 4 = 126

b = 122

a + a - 2 + a - 4 + a - 6 + a - 8 = 5 * 251

5a - 20 = 5 * 251

a - 4 = 251

a = 255

Hence, the required difference = 255 - 122 = 133

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