Previous Year Questions

From I:

Ratio of Rice to Tea in mixture A = 150%: 100% = 3: 2

Amount of rice in mixture A = 3(x + 20)/5

Amount of tea in mixture A = 2(x + 20)/5

Since we are not given any information of mixture B.

Statement I alone is not sufficient.

From II:

Amount of tea in mixture B = 3(x - 19)/7

Amount of sugar in mixture B = 4(x - 19)/7

Since we are not given any information of mixture A.

Statement II alone is not sufficient.

From I and II:

From statement I we get:

Amount of rice in mixture A = 3(x + 20)/5

Amount of tea in mixture A = 2(x + 20)/5

From statement II we get:

Amount of tea in mixture B = 3(x - 19)/7

Amount of sugar in mixture B = 4(x - 19)/7

According to question-

[2(x + 20)/5] - [3(x - 19)/7] = 15

14x + 280 - 15x + 285 = 15 * 35

x + 525 = 565

x = 40

Amount of tea in the final mixture B = [3(x - 19)/7] + (9/20) * [2(x + 20)/5] = 9 + 10.8 = 19.8 kg

Amount of sugar in the final mixture B = 4(x - 19)/7 = 12 kg

Required per cent = [(19.8 - 12)/12] * 100 = 65%

Statements I and II together are sufficient.