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Question :

The volume of a cube is 46656 cm3 in which four maximum possible sizes of circles are drawn on each face. The remaining part of the cube is painted blue color at the rate of Rs. 24.5 per cm2 and the circle drawn on each face of the cube is painted red color at the rate of Rs. __ per cm2. If the total cost of painting the entire cube is Rs. 104976 , then find the value that can fill the blank.

1. Rs. 17.5

2. Rs. 3.5

3. Rs. 28

4. Rs. 21

5. Rs. 10.5

Correct Answer : 5
Solution :

Volume of the cube = Side * Side * Side

Side3 = 46656 cm3

Side = 36 cm

Four circles on each face on the cube means the diameter of each circle = 36/2 = 18 cm

Diameter of circle = 2 * Radius of the circle

The radius of the circle = Diameter of the circle/2

= 18/2

= 9 cm

The total number of circles drawn = 4 * the total number of faces of the cube

= 4 * 6

= 24

The total surface area of the cube = 6 * Side2

= 6 * 362

= 7776 cm2

The area of a circle = π r2

The area of 24 circles = 24 * π * 92

= 42768/7 cm2

The area of the remaining part of the cube = 7776 - 42768/7

= (54432 - 42768)/ 7

= 11664/7 cm2

The total cost of painting the remaining part of the cube = 11664/7 * 24.5

= Rs. 40824

Let the value that can fill the blank be 'a.

The cost of painting the 24 circles = The total cost of painting the entire cube - The total cost of painting the remaining part =

=> Rs. 104976 - Rs. 40824 = 42768/7 * a

=> Rs. 64152 = 42768/7 * a

=> a = 64152 * 7/ 42768

=> a = Rs. 10.5

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