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Previous Year Questions

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Question :

There are three taps of diameter 2 cm, 3 cm, and 4 cm, respectively. The ratio of the water flowing through them is equal to the ratio of the square of their diameters. The biggest tap can fill an empty tank alone in 81 min. If all the taps are opened simultaneously, then how long will the tank take (in min) to be filled?

1. 34(20/29)

2. 64(20/29)

3. 54(20/29)

4. 44(20/29)

Correct Answer : 4
Solution :

Time taken to fill the tank by the tap having 4 cm diameter = 81 min

Time taken to fill the tank by the tap having 2 cm diameter= 81 * (4/2) 2 = 324min

Similarly, time taken to fill the tank by the tap having 3 cm diameter= 81 * (4/3) 2 =144min

Part of the tank filled by all the three pipes in 1 minute = 1/81 + 1/324 + 1/144 = 29/1296

Hence, required time taken = 1296/29 = 44(20/29) min

SSC CGL Tier II Previous Year Papers

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