Quantity I:
Let, ages of Nitin and Madan before four years be 5k years and 6k years respectively.
According to the question
(5k + 8)/(6k + 8) = 7/8
=> 8 x (5k + 8) = 7 x (6k + 8)
=> 40k + 64 = 42k + 56
=> 42k - 40k = 64 - 56
=> 2k = 8
=> k = 8/2
=> k = 4
Present age of Nitin = 5k + 4 = 5 x 4 + 4 = 24 years
Present age of Madan = 6k + 4 = 6 x 4 + 4 = 28 years
Present age of Rama = (24 + 28)/2 = 52/2 = 26 years
Age of Rama after four years = 26 + 4 = 30 years
Quantity II:
Sahu + Rahu + Bahu = 3 x 28
=> Sahu + Rahu + Bahu = 84 ----------- (i)
Sahu + Rahu = 2 x 37 - 2 x 4
=> Sahu + Rahu = 74 - 8
=> Sahu + Rahu = 66 ------------ (ii)
From (i) and (ii)
66 + Bahu = 84
=> Bahu = 84 - 66
=> Bahu = 18 years
Age of Bahu after six years = 18 + 6 = 24 years
Hence, Quantity I > Quantity II
Study Notes
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