Previous Year Questions

Option a:

#=BNQ, %=NFM

So,

BNQ : DKR :: PCL: NFM

BNQ : DKR = B(2) N(14) Q(17) :D(2+2) K(14-3) R(17+1)

PCL: NFM = P(16) C(3) L(12) :N(16-2) F(3+3) M(12+1)

The relation should be same which is not same in this case.

Option b:

#=FHT, %=NFJ

So,

FHT : DKR :: PCL: NFJ

FHT : DKR = F(6) H(8) T(20) :D(6-2) K(8+3) R(20-2)

PCL: NFJ = P(16) C(3) L(12) : N(16-2) F(3+3) J(12-2)

The relation is same.

Option c:

#=COQ, %=OGH

So,

COQ: DKR :: PCL: OGH

COQ: DKR= C(3) O(15) Q(17) :D(3+1) K(15-4) R(17+1)

PCL: OGH= P(16) C(3) L(12) : O(16-1) G(3+4) H(12-4)

The relation should be same which is not same in this case.

Option d:

#= BNP, %=NFJ

So,

BNP : DKR :: PCL: NFJ

BNP : DKR= B(2) N(14) P(16) :D(2+2) K(14-3) R(16+2)

PCL: NFJ = P(16) C(3) L(12) :N(16-2) F(3+3) J(12-2)

The relation should be same which is not same in this case.

Thus, Option (b) is correct.